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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2004

  • question_answer
    If length of wire is 2m and the mass is 80 kg, the tension in wire will be if frequency is \[\frac{1}{4}\]Hz:            

    A)              400 N                       

    B)              80 N

    C)              4 N                           

    D)              4000 N

    Correct Answer: B

    Solution :

                      \[n=\frac{1}{2l}\sqrt{\left( \frac{T}{m} \right)}\] \[\therefore \]  \[T={{(2nl)}^{2}}\times m\]                     \[={{\left( 2\times \frac{1}{4}\times 2 \right)}^{2}}\times 80=80N\]


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