A) 188 kPa
B) 8.4 kPa
C) 18.8 kPa
D) 84 kPa
Correct Answer: D
Solution :
Bulk modulus is given by \[K=\frac{\Delta P}{\Delta V/V}\] ?(i) Given : \[K=2100\,\times {{10}^{6}}\,Pa\,V=200\,lit.,\] \[\Delta V=200\times \frac{0.004}{100}=0.008\,\text{lit}\] Putting the given values in eq (i) \[2100\times {{10}^{6}}\frac{\Delta P}{0.008/200}\] so, \[\Delta P=\frac{2100\times {{10}^{6}}\times 0.008}{200}\] \[=84000Pa=84\times {{10}^{3}}\] \[=84kPa\]
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