A) 1638 J
B) 1019 J
C) 1568 J
D) 836 J
Correct Answer: A
Solution :
\[\Delta Q=\mu {{C}_{V}}\Delta T\] Here: \[\mu =\frac{2}{4}=\frac{1}{2}\] \[{{C}_{v}}=M{{E}_{\upsilon }}=4\times 3=12\] At constant volume \[\frac{{{P}_{2}}}{{{P}_{1}}}=\frac{{{T}_{2}}}{{{T}_{1}}}\] But \[{{P}_{2}}=2{{P}_{i}}\](given) \[\therefore \] \[{{T}_{2}}=2{{T}_{1}}=2\times 273K\] or \[\Delta T={{T}_{2}}={{t}_{1}}=273K\] so, \[\Delta Q=\frac{1}{2}\times 12\times 273=1638J\]
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