A) \[Pb{{(N{{O}_{3}})}_{2}}\]
B) \[PbC{{O}_{3}}Pb{{(OH)}_{2}}\]
C) \[Pb{{(OH)}_{2}}4PbC{{O}_{3}}\]
D) \[P{{b}_{3}}{{O}_{4}}\]
Correct Answer: D
Solution :
Sindoor is red lead,\[P{{b}_{3}}{{O}_{4}}.\]
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