A) \[3.01\times {{10}^{24}}\]
B) \[4.06\times {{10}^{24}}\]
C) \[2.01\times {{10}^{24}}\]
D) \[3.02\times {{10}^{24}}\]
Correct Answer: A
Solution :
We know that protons in 1 mole\[CaC{{O}_{3}}\] = atomic number of calcium + atomic number of carbon + 3 (atomic number of oxygen) \[=20+6+3(8)\] \[=50\,\,moles\] \[\therefore \]proton in\[10\,\,g\] \[CaC{{O}_{3}}=\frac{10\times 50}{100}\times 6.02\times {{10}^{23}}\] \[=3.01\times {{10}^{24}}\]
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