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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2005

  • question_answer
    \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\xrightarrow{Sm/HCl}{{C}_{6}}{{H}_{5}}X\] is identified as:

    A) \[NO\]                                 

    B) \[-N{{H}_{2}}\]

    C) \[NHOH\]           

    D)         none of these

    Correct Answer: B

    Solution :

    \[\underset{Nitrobenzene}{\mathop{{{C}_{6}}{{H}_{5}}N{{O}_{2}}}}\,\xrightarrow{Sn/HCl}\underset{Aniline}{\mathop{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}}\,\] Nitrobenzene on reduction with \[Sn\] and \[HCl\] produce aniline. Hence, \[X\] is identified as\[-N{{H}_{2}}\]group.


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