A) \[\frac{9.8}{2\sqrt{2}}m/{{s}^{2}}\]
B) \[\frac{9.8}{\sqrt{2}}m/{{s}^{2}}\]
C) \[9.8\,m/{{s}^{2}}\]
D) \[4.8\,m/{{s}^{2}}\]
Correct Answer: A
Solution :
Here: Angle of plane is inclined = \[45{}^\circ \] Coefficient of friction \[\mu \] = 0.5 Tile deceleration of the body sliding on the inclined plane is given by \[=g(\sin \text{-}\mu \,\text{cos }\text{)}\] \[=9.8(\sin \,45{}^\circ -0.5\,\cos \,45{}^\circ )\] \[=9.8\left( \frac{1}{\sqrt{2}}-0.5\times \frac{1}{\sqrt{2}} \right)\] \[=\frac{9.8}{2\sqrt{2}}m/{{s}^{2}}\]
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