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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2005

  • question_answer
    From a point charge, there is a fixed point A. At A, there is an electric field of 500 volt/meter and potential difference of 3000 V. Distance between the point charge and A is  

    A)  24 m                                    

    B)  16 m

    C)  12 m                    

    D)         6 m

    Correct Answer: D

    Solution :

    Here: Electric field E = 500 V/m Potential difference V = 3000 V Electric field E is given by \[E=\frac{V}{d}\] \[500=\frac{3000}{d}\] So,          \[d=\frac{3000}{500}=6\,m\]


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