A) \[12\,\pi \]
B) \[8\,\pi \]
C) \[5\,\pi \]
D) \[2\,\pi \]
Correct Answer: C
Solution :
Here: Mutual inductance between two coils M = 0.005 H Peak current \[{{l}_{0}}=10\] amp Angular frequency (\[\omega \]= 100 \[\pi \] rad/sec The current\[l={{l}_{0}}\,\sin \,\omega \,t\] or \[\frac{d}{dt}=\frac{d}{dt}({{l}_{0}}\,\sin \,\omega \,t)\] \[={{l}_{0}}\cos \,\omega \,t.\,\omega \] \[=10\times 1\times 100\pi \] \[=1000\pi \] Hence, induced emf is given by \[e=M\times \frac{di}{di}=0.005\times 1000\times \pi \] \[=5\pi \,V\]You need to login to perform this action.
You will be redirected in
3 sec