A) zero
B) \[\frac{L}{2}\]
C) L
D) 2 L
Correct Answer: B
Solution :
Here: Inductance of 1st inductor\[{{L}_{1}}=L\] Inductance of \[\text{I}{{\text{I}}^{\text{nd}}}\] inductor \[{{L}_{2}}=L\] Now if these inductors are connected in parallel their equivalent inductance will be \[\frac{1}{{{L}_{eq}}}=\frac{1}{{{L}_{1}}}+\frac{1}{{{L}_{2}}}=\frac{1}{L}+\frac{1}{L}=\frac{2}{L}\] Hence, \[{{L}_{eq}}=\frac{L}{2}\]
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