A) 4 : 1
B) 2 : 1
C) 1 : 2
D) 1 : 1
Correct Answer: A
Solution :
The gas equation is \[PV=nRT\] Suppose \[{{n}_{1}}\] and \[{{n}_{2}}\] moles of the gas be in jar .4 and jar B respectively Then\[{{P}_{1}}{{V}_{1}}={{n}_{1}}R{{T}_{1}}\] \[{{P}_{2}}{{V}_{2}}={{n}_{2}}R{{T}_{2}}\] \[\frac{{{n}_{2}}}{{{n}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}{{T}_{1}}}{{{P}_{1}}{{V}_{1}}{{T}_{2}}}\] For jar A \[\begin{align} & {{P}_{1}}=P \\ & {{V}_{1}}=V \\ \end{align}\] For jar B \[{{P}_{2}}=2P\] \[\begin{align} & {{V}_{2}}=V/4 \\ & {{T}_{2}}=2T \\ \end{align}\] \[\frac{{{n}_{2}}}{{{n}_{1}}}=\frac{2PVT}{PV\times 4\times 2T}=\frac{1}{4}\] \[\frac{{{n}_{1}}}{{{n}_{2}}}=\frac{4}{1}\]
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