A) 1 m/s
B) 2 m/s
C) 0.5 m/s
D) 15 m/s
Correct Answer: B
Solution :
\[y=5\times {{10}^{-5}}\,\sin \,(100t-50x)\] Comparing with the standard equation \[y=A\,\sin \,(\omega t-kx)\] \[k=50\Rightarrow \frac{2\pi }{\lambda }=50\,\Rightarrow \lambda =\frac{2\pi }{50}m\] \[\omega =100\Rightarrow n\frac{100}{2\pi }per\,\sec \] \[\therefore \]Velocity of wave \[\upsilon =n\lambda \] \[=\frac{100}{2\pi }\times \frac{2\pi }{50}=2\,m/s\]
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