A) \[b+2ct,\,2c\]
B) \[b,\,\,2\,c\]
C) \[\,2\,c,\,b\]
D) \[\,b+2c,\,2c\]
Correct Answer: B
Solution :
\[s=a+bt+c{{t}^{2}}\] \[\Rightarrow \] \[v=\frac{ds}{dt}=b+2ct\] \[\Rightarrow \] Initial velocity\[={{\left| \frac{ds}{dt} \right|}_{t=0}}=b\] and \[a=\frac{dv}{dt}=2c\] \[\Rightarrow \]Initial acceleration\[={{\left| \frac{dv}{dt} \right|}_{t=0}}=2c\]
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