A) \[FeS{{O}_{4}}\cdot NO\]
B) \[[Fe{{(S{{O}_{4}})}_{2}}\cdot NO]{{H}_{2}}O\]
C) \[F{{e}_{2}}{{(S{{O}_{4}})}_{3}}\cdot NO\]
D) none of these
Correct Answer: A
Solution :
Brown ring in the ring-test of \[NO_{3}^{-}\] is formed due to the formation of\[FeS{{O}_{4}}\]. \[NO\] at the junction of two liquids.
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