A) acetic acid
B) bromoaceric acid
C) methyl amine
D) ethyl amine
Correct Answer: C
Solution :
This is Hofmann-bromamide reaction. In this reaction one carbon less amines are formed from amides. \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow{B{{r}_{2}}/KOH}\underset{\text{Methyl}\,\,\text{amine}}{\mathop{C{{H}_{3}}N{{H}_{2}}}}\,\]
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