RAJASTHAN PMT Rajasthan - PMT Solved Paper-2006

  • question_answer
    A source is approaching a stationary observer with velocity\[{{\left( \frac{1}{10} \right)}^{th}}\]that of sound. Ratio of observed and real frequencies will be :

    A)  \[\frac{9}{10}\]                               

    B)         \[\frac{11}{10}\]

    C)         \[\frac{10}{11}\]                                             

    D)         \[\frac{10}{9}\]

    Correct Answer: D

    Solution :

    From the relation, \[f={{f}_{0}}\left[ \frac{{{v}_{sound}}-{{v}_{observer}}}{{{v}_{sound}}-{{v}_{source}}} \right]\] \[{{v}_{observer}}=0\], because observer is stationary, \[\Rightarrow \]               \[f={{f}_{0}}\left[ \frac{v}{v-\frac{v}{10}} \right]={{f}_{0}}\left[ \frac{1}{\frac{9}{10}} \right]\] \[\Rightarrow \]               \[\frac{f}{{{f}_{0}}}=\frac{10}{9}\]


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