A) \[\frac{10}{\sqrt{2}}A\]
B) \[\frac{5}{\sqrt{2}}A\]
C) \[20\sqrt{2}A\]
D) \[10\sqrt{2}A\]
Correct Answer: D
Solution :
Ammeter reads the root mean square value of current \[({{i}_{rms}}).{{i}_{rms}}\] related to the peak value of current \[({{i}_{0}})\] the relation. \[{{i}_{rms}}=\frac{{{i}_{0}}}{\sqrt{2}}\] \[\Rightarrow \] \[{{i}_{0}}=\sqrt{2}\times {{i}_{rms}}=\sqrt{2}\times 10\,\,A\] \[=10\sqrt{2}A\]
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