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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2006

  • question_answer
    The minimum wavelength of X-rays emitted by X-ray tube is \[0.4125\,\overset{\text{o}}{\mathop{\text{A}}}\,\]. The accelerating voltage is :

    A)  30 kV                                   

    B)         50 kV

    C)         80 kV                                   

    D)                                         60 kV

    Correct Answer: A

    Solution :

    From the formula                 \[eV=\frac{hc}{\lambda }\]                 \[V=\frac{hc}{e\lambda }\]                    \[=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.6\times {{10}^{-19}}\times 0.4125\times {{10}^{-10}}}\]                    \[=30\times {{10}^{3}}V\]                    \[=30\,\,kV\]


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