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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2006

  • question_answer
    When a wave travels in a medium the particles displacement is given by the equation y = 0.03 sin n (2t - 0.01 x), where x and y are in metre and r in second. The wavelength of the wave is :

    A)  200 m                                  

    B)         100 m                  

    C)         20 m                                    

    D)         10 m

    Correct Answer: A

    Solution :

    Here, displacement equation is                 \[y=0.03\,\,\sin \,\,\pi (2t-0.01x)\]           ... (i) The standard equation is                 \[y=a\,\,\sin \,\,2\pi \left( \frac{t}{T}-\frac{x}{\lambda } \right)\]                              ... (ii) Comparing the given Eq. (i) with standard Eq. (ii), we have                 \[\frac{2}{\lambda }=0.01\] or            \[\lambda =\frac{2}{0.01}\]                                 \[=200\,\,m\].


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