A) propanol-2
B) butanol-2
C) ethanol
D) methanol
Correct Answer: B
Solution :
Optical isomerism is shown by an asymmetric carbon atom which has a carbon atom attached to four different atoms or groups. So, butanol-2 is optically active. \[{{H}_{3}}C-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ O{{H}_{2}} \end{smallmatrix}}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}\]
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