question_answer

In the following reaction,                 \[{{C}_{2}}{{H}_{2}}\xrightarrow[HgS{{O}_{4}}/{{H}_{2}}S{{O}_{4}}]{{{H}_{2}}O}XC{{H}_{3}}CHO\] What is\[X\]?

A) \[C{{H}_{3}}C{{H}_{2}}OH\]                        

B)        \[C{{H}_{3}}-O-C{{H}_{3}}\]

C)        \[C{{H}_{3}}C{{H}_{2}}CHO\]     

D)        \[C{{H}_{2}}=CHOH\]

Correct Answer: D

Solution :

\[HC\equiv CH\xrightarrow[\begin{smallmatrix}  HgS{{O}_{4}}/{{H}_{2}}S{{O}_{4}} \\  \,\,\,\,\,\,\,\,\,\,{{60}^{o}}C \end{smallmatrix}]{{{H}_{2}}O}\]