A) \[AlC{{l}_{3}}\cdot 6{{H}_{2}}O\]
B) \[AlC{{l}_{3}}\]
C) \[SnC{{l}_{4}}\]
D) \[FeC{{l}_{3}}\]
Correct Answer: A
Solution :
\[AlC{{l}_{3}}\] is \[sp\] hybridised. When it combines with six \[{{H}_{2}}O\] molecules, one of the vacant \[p-\] orbitals and five \[d-\]orbitals are filled by electrons pairs, as a result of which it cannot accept more electrons and so, will not act as electron acceptor of Lewis acid.
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