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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2007

  • question_answer
    Degree of dissociation of\[0.1\,\,N\,\,C{{H}_{3}}COOH\], is\[({{K}_{acid}}=1\times {{10}^{-5}})\]

    A) \[{{10}^{-5}}\]                                  

    B)        \[{{10}^{-4}}\]

    C)        \[{{10}^{-3}}\]                                  

    D)        \[{{10}^{-2}}\]

    Correct Answer: D

    Solution :

    \[\alpha =\sqrt{\frac{{{K}_{a}}}{C}}=\sqrt{\frac{1.0\times {{10}^{-5}}}{0.1}}\]                   \[=\sqrt{1.0\times {{10}^{-4}}}=1.0\times {{10}^{-2}}\]


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