RAJASTHAN PMT Rajasthan - PMT Solved Paper-2007

  • question_answer
    \[3A\to 2B\]rate of reaction\[\frac{+d[B]}{dt}\]is equal to

    A) \[-\frac{3}{2}\frac{d[A]}{dt}\]                   

    B)        \[-\frac{2}{3}\frac{d[A]}{dt}\]

    C)        \[-\frac{1}{3}\frac{d[A]}{dt}\]                   

    D)        \[+2\frac{d[A]}{dt}\]

    Correct Answer: B

    Solution :

    \[3A\xrightarrow{{}}2B\] Rate\[=-\frac{1}{3}\frac{d[A]}{dt}=\frac{1}{2}\frac{d[B]}{dt}\] Multiply both rates by 2 Rate\[=2\left[ -\frac{1}{3}\frac{d[A]}{dt} \right]=\frac{d[B]}{dt}\]         \[=\frac{-2}{3}\frac{d[A]}{dt}=\frac{d[B]}{dt}\]


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