question_answer

Number of electrons surrounding \[Kr\] in\[Kr{{F}_{2}}\]is

A) \[10\]                                   

B)        \[6\]

C)        \[4\]                                     

D)        \[8\]

Correct Answer: A

Solution :

Krypton \[(Kr)\] forms two covalent bonds with two fluorine atoms (one with each fluorine). Number of electrons in valence shell of\[Kr=8.\] Number of electrons it shares with two \[F-\]atoms\[=2\] \[\therefore \]Total number of electrons found around \[Kr\] in\[KrF\]                                 \[=8+2=10\]