RAJASTHAN PMT Rajasthan - PMT Solved Paper-2007

  • question_answer
    A cosmonaut is orbiting earth in a spacecraft at an altitude h = 630 km with a speed of 8 km/s. If the radius of the earth is 6400 km, the acceleration of the cosmonaut is

    A)  \[9.10\,m/{{s}^{2}}\]                                    

    B)  \[9.80\,m/{{s}^{2}}\]

    C)  \[10.0\,m/{{s}^{2}}\]   

    D)         \[9.88\,m/{{s}^{2}}\]

    Correct Answer: A

    Solution :

    Acceleration of cosmonaut is                 \[a=\frac{{{v}^{2}}}{r}\] where \[r\] is the distance of cosmonaut from earths centre. Given,\[v=8\,\,km/s=8000\,\,m/s.\] \[r=(6400+630)km=(6400+630)\times 1000\,\,m\] \[\therefore \]  \[a=\frac{{{(8000)}^{2}}}{(6400+630)\times 1000}\]                    \[=9.10\,\,m/{{s}^{2}}\]


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