A) no current flows
B) the depletion region is increased
C) the depletion region is reduced
D) the height of the potential barrier is reduced
Correct Answer: B
Solution :
In reverse biasing, the applied voltage \[V\] on the n-side is positive and is negative on the p-side. The applied bias \[V\] and the barrier potential \[{{V}_{B}}\] are in the same direction making the effective junction potential\[V+{{V}_{B}}\]. As a result, the junction width will increase. The higher junction potential restricts the How of majority carriers to a much greater extent. However, such a field will favour the How of minority carriers. So, reverse bias current will be due to the minority carriers only.
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