A) \[\frac{13.6}{11}eV\]
B) \[\frac{13.6}{{{(11)}^{2}}}eV\]
C) \[13.6\times {{(11)}^{2}}eV\]
D) \[13.6\,eV\]
Correct Answer: C
Solution :
The Bohr model of hydrogen atom can be extended to hydrogen like atoms. Energy of such an atom is given by \[{{E}_{n}}=-13.6\frac{{{Z}^{2}}}{{{n}^{2}}}\] Here, \[Z=11\] for \[Na\] atom; 10 electrons are removed already, so it is 10 limes ionised. For the last electron to be removed,\[n=1\] \[\therefore \] \[{{E}_{n}}=\frac{13.6{{(11)}^{2}}}{{{(1)}^{2}}}eV\] or \[{{E}_{n}}=-13.6\times {{(11)}^{2}}eV\]
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