A) A and B have .same specific heats
B) Specific heat of A is less
C) Specific heat of B is less
D) Nothing can be said
Correct Answer: B
Solution :
According to Newtons law of cooling rate of cooling is given by \[\left( \frac{-dT}{dt} \right)=\frac{eA\sigma }{mc}({{T}^{4}}-T_{0}^{4})\] where \[c\]is specific heat of material. or \[\left( \frac{-dT}{dt} \right)\propto \frac{1}{c}\] \[ie\], rate of cooling varies inversely as specific heat. From the graph, for \[A\] rate of cooling is larger. Therefore, specific heat of \[A\] is smaller.
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