A) \[y=A\,\sin \,(kx-\omega t)\]
B) \[x=A\,\sin \,(ky-\omega t)\]
C) \[y=A\,\sin \,(ky\cos \omega t\]
D) \[y=A\,\,\cos ky\sin \omega t\]
Correct Answer: B
Solution :
The equation given is \[x=A\sin (ky-\omega t)\] represents a wave travelling along \[y-\]axis, where \[A\] is its amplitude.
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