RAJASTHAN PMT Rajasthan - PMT Solved Paper-2008

  • question_answer
    What is the wave number of 4th line in Balmer series of hydrogen spectrum?                 \[(R=1,09,677\text{ }c{{m}^{-1}})\]

    A) \[24,630\,\,c{{m}^{-1}}\]                             

    B)        \[23,360\,\,c{{m}^{-1}}\]

    C)        \[24,730\,\,c{{m}^{-1}}\]                             

    D)        \[24,372\,\,c{{m}^{-1}}\]

    Correct Answer: D

    Solution :

    \[\bar{v}=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] For Balmer series \[{{n}_{1}}=2\] and for 4th line in Balmer series\[{{n}_{2}}=6\] \[\because \]     \[R=109677\,\,c{{m}^{-1}}\]                 \[v=109677\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{6}^{2}}} \right)\]                    \[=109677\left( \frac{1}{4}-\frac{1}{36} \right)\]                 \[\bar{v}=23,372\,\,c{{m}^{-1}}\]


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