A) \[C{{H}_{3}}-C{{H}_{2}}-COOH\]
B) \[C{{H}_{2}}=CH-C{{H}_{2}}OH\]
C) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH\]
D) \[C{{H}_{3}}-C{{H}_{2}}-CHO\]
Correct Answer: B
Solution :
\[LiAl{{H}_{4}}\] reduces \[-COOH\]to\[-C{{H}_{2}}OH\] without affecting \[C=C\] bond.
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