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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2008

  • question_answer
    \[25\,\,mL\] of a solution of barium hydroxide on titration with \[0.1\] molar solution of hydrochloric acid gave a titre value of \[35\,\,mL\]. The molarity of barium hydroxide solution was

    A) \[0.07\]                               

    B)        \[0.14\]

    C)        \[0.28\]                               

    D)        \[0.35\]

    Correct Answer: A

    Solution :

    Let molarity of\[Ba{{(OH)}_{2}}={{M}_{1}}\] Normality\[=2{{M}_{1}}\] Molarity of\[HCl=0.1M=0.1N\]                 \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\]                 \[2{{M}_{1}}\times 25=0.1\times 35\]                 \[{{M}_{1}}=0.07M\]


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