RAJASTHAN PMT Rajasthan - PMT Solved Paper-2008

  • question_answer
    If at \[298\,\,K\] the bond energies of \[C-H,\,\,C-C,\]\[C=C\] and \[H-H\] bonds are respectively \[414,\,\,347,\,\,615\] and \[435\,\,kJ\,\,mo{{l}^{-1}}\], the value of enthalpy change for the reaction \[{{H}_{2}}C=C{{H}_{2}}(g)+{{H}_{2}}(g)\xrightarrow{{}}{{H}_{2}}C-C{{H}_{2}}(g)\] at \[298\,\,K\] will be

    A) \[+250\,\,kJ\]                   

    B)        \[-250\,\,kJ\]

    C)        \[+125\,\,kJ\]                   

    D)        \[-125\,\,kJ\]

    Correct Answer: D

    Solution :

    \[C{{H}_{2}}=C{{H}_{2}}+{{H}_{2}}\xrightarrow{{}}C{{H}_{3}}-C{{H}_{3}}\] \[\Delta H={{(BE)}_{\text{reactants}}}-{{(BE)}_{\text{products}}}\] \[=4{{(BE)}_{C-H}}+{{(BE)}_{C=C}}+{{(BE)}_{H-H}}\] \[-[6{{(BE)}_{C-H}}+{{(BE)}_{C-C}}]\] \[=-125\,\,kJ\]


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