RAJASTHAN PMT Rajasthan - PMT Solved Paper-2008

  • question_answer
    The radionuclide \[_{90}^{234}Th\] undergoes two successive \[\beta -\]decays followed by one\[\alpha -\]decay. The atomic number and the mass number respectively of the resulting radionuclide are

    A)  92 and 234         

    B)         94 and 230

    C)         90 and 230         

    D)         92 and 230

    Correct Answer: C

    Solution :

    \[_{90}^{234}Th\xrightarrow{-\beta }\xrightarrow{-\beta }_{92}^{234}X\xrightarrow{-\alpha }_{90}^{230}Y\]


You need to login to perform this action.
You will be redirected in 3 sec spinner