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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2008

  • question_answer
    If \[{{M}_{O}}\] is the mass of an oxygen isotope \[_{8}{{O}^{17}}\]\[{{M}_{p}}\] and \[{{M}_{n}}\] are the masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is

    A)  \[({{M}_{0}}-8{{M}_{p}}){{c}^{2}}\]       

    B)  \[({{M}_{0}}-8{{M}_{p}}-9{{M}_{n}}){{c}^{2}}\]

    C)  \[{{M}_{0}}{{c}^{2}}\]                  

    D)         \[({{M}_{0}}-17{{M}_{n}}){{c}^{2}}\]

    Correct Answer: B

    Solution :

    Binding energy                 \[BE=({{M}_{nucleus}}-{{M}_{nucleons}}){{c}^{2}}\]                       \[=({{M}_{O}}-8{{M}_{P}}-9{{M}_{n}}){{c}^{2}}\]


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