A) \[\text{ }\!\![\!\!\text{ }{{\text{L}}^{\text{-1}}}\text{T }\!\!]\!\!\text{ }\]
B) \[\text{ }\!\![\!\!\text{ }{{\text{L}}^{\text{2}}}{{\text{T}}^{2}}\text{ }\!\!]\!\!\text{ }\]
C) \[\text{ }\!\![\!\!\text{ }{{\text{L}}^{\text{2}}}{{\text{T}}^{-2}}\text{ }\!\!]\!\!\text{ }\]
D) \[\text{ }\!\![\!\!\text{ L}{{\text{T}}^{-1}}\text{ }\!\!]\!\!\text{ }\]
Correct Answer: C
Solution :
Velocity is given by \[v=\frac{1}{\sqrt{{{\mu }_{0}}{{\varepsilon }_{0}}}}\] \[\therefore \] \[{{v}^{2}}=\frac{1}{{{\mu }_{0}}{{\varepsilon }_{0}}}={{[L{{T}^{-1}}]}^{2}}\] \[\therefore \] \[\frac{1}{{{\mu }_{0}}{{\varepsilon }_{0}}}=[{{L}^{2}}{{T}^{-2}}]\]
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