2. Solved Papers
  3. RAJASTHAN PMT

RAJASTHAN PMT Rajasthan - PMT Solved Paper-2008

  • question_answer
    A nucleus with Z=92 emits the following in a sequence: \[\alpha ,\,\alpha ,\,{{\beta }^{-}},\,{{\beta }^{-}},\,\alpha ,\,\alpha ,\,\alpha ,\,\alpha ,\,{{\beta }^{-}},\,{{\beta }^{-}},\,\alpha ,\,{{\beta }^{+}},\,{{\beta }^{+}},\,\alpha \]. The Z of the resulting nucleus is

    A)  76                                         

    B)  78

    C)  82                         

    D)         74

    Correct Answer: B

    Solution :

    Since, \[8\alpha -\]particles \[4{{\beta }^{-}}-\]particles and \[2{{\beta }^{+}}-\]particles are emitted, so new atomic number                 \[Z=Z-8\times 2+4\times 1-2\times 1\]                      \[=92-16+4-2\]                      \[=92-14\]                                 = 78


You need to login to perform this action.
You will be redirected in 3 sec spinner