A) 7
B) 4
C) 3
D) 8
Correct Answer: A
Solution :
Isomers of compound having molecular formula\[{{C}_{4}}{{H}_{10}}O\] (i)\[\underset{1-\text{butanol}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-OH}}\,\] (ii)\[\underset{2-\text{butanol}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}}}\,\] (iii)\[\underset{2methy\,\,2-propanol}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}}}\,\] (iv)\[\underset{2-methyl\,\,1-propanol}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{2}}-OH}}\,\] (v)\[\underset{1-methoxy\,\,propane}{\mathop{C{{H}_{3}}-O-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}}}\,\] (vi)\[\underset{1-ethoxy\,\,ethane}{\mathop{C{{H}_{3}}-C{{H}_{2}}-O-C{{H}_{2}}-C{{H}_{3}}}}\,\] (vii)\[\underset{1-methoxy\,\,1-methyl\,\,ethane}{\mathop{C{{H}_{3}}-O-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}}}\,\]
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