A) \[_{96}^{242}Cm(\alpha ,\,\,2m)_{97}^{243}Bk\]
B) \[_{5}^{10}B(\alpha ,\,\,n)_{7}^{13}N\]
C) \[_{7}^{14}N(n,\,\,p)_{6}^{14}C\]
D) \[_{14}^{28}Si(d,\,\,n)_{15}^{29}P\]
Correct Answer: A
Solution :
(a)\[_{99}C{{m}^{242}}+2{{\alpha }^{4}}{{\xrightarrow{{}}}_{97}}B{{k}^{243}}+{{2}_{0}}{{n}^{1}}\] (b)\[_{5}{{B}^{10}}{{+}_{2}}{{\alpha }^{4}}{{\xrightarrow{{}}}_{7}}{{N}^{13}}{{+}_{0}}{{n}^{1}}\] (c)\[_{7}{{N}^{14}}+_{0}^{1}n{{\xrightarrow{{}}}_{6}}{{C}^{14}}{{+}_{1}}{{p}^{1}}\] (d)\[_{14}S{{i}^{28}}{{+}_{1}}{{d}^{2}}{{\xrightarrow{{}}}_{15}}{{P}^{29}}{{+}_{0}}{{n}^{1}}\] Charge and mass in equation (a) is not same.
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