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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2009

  • question_answer
    The electric field between two parallel plates of a capacitor is \[2.1\,\times {{10}^{-5}}\]. If a medium is inserted between the plates than the electric field becomes \[1.0\,\times {{10}^{-5}}\]. Now, the value of dielectric will be

    A)  2                                            

    B)  3

    C)  4                            

    D)         5

    Correct Answer: A

    Solution :

                    \[E=\frac{\sigma }{{{\varepsilon }_{0}}}=2.1\times {{10}^{-5}}\]                 \[E=\frac{\sigma }{{{\varepsilon }_{0}}K}=1\times {{10}^{-5}}\] \[\therefore \]  \[\frac{E}{E}=\frac{\sigma }{{{\varepsilon }_{0}}}\times \frac{{{\varepsilon }_{0}}K}{\sigma }=\frac{2.1\times {{10}^{-5}}}{1\times {{10}^{-5}}}\]        or            \[K=2.1\approx 2\]


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