A) \[10{}^\circ \]
B) \[24{}^\circ \]
C) \[50{}^\circ \]
D) \[1/6{}^\circ \]
Correct Answer: B
Solution :
Given,\[{{f}_{o}}=60\,\,cm,\,\,{{f}_{e}}=5\,\,cm\] Visual angle\[(\alpha )={{2}^{o}}\] Visual angle\[(\beta )=?\] Magnifying power of a telescope\[(M)=\frac{{{f}_{o}}}{{{f}_{e}}}=\frac{\beta }{\alpha }\] \[\therefore \] \[\beta =\alpha \frac{{{f}_{o}}}{{{f}_{e}}}={{2}^{o}}\times \frac{60}{5}={{24}^{o}}\]
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