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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2009

  • question_answer
    Two waves are given by\[=a\sin (\omega t-kx)\]and \[{{y}_{2}}=a\cos (\omega t-kx).\]The phase difference between the two waves is

    A)  \[\text{/4}\]                     

    B)         \[\]

    C)  \[\text{/8}\]                     

    D)         \[\text{/2}\]

    Correct Answer: D

    Solution :

    Waves equations are                 \[{{y}_{1}}=a\sin (\omega t-kx)\] and        \[{{y}_{2}}=a\cos (\omega t-kx)\]                 \[{{y}_{2}}=a\sin \left( \omega t-kx+\frac{\pi }{2} \right)\] \[\therefore \]Phase difference between the waves\[=\frac{\pi }{2}\]


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