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  3. RAJASTHAN PMT

RAJASTHAN PMT Rajasthan - PMT Solved Paper-2009

  • question_answer
    The potential energy of a body is given by \[U=A-B{{x}^{2}}\] (where x is the displacement). The magnitude of force acting on the particle is

    A)  constant            

    B)         proportional to x            

    C)  proportional to \[{{x}^{2}}\]

    D)             proportional to 1/x

    Correct Answer: B

    Solution :

    Potential energy\[U=A-B{{x}^{2}}\] Force\[F=\frac{dU}{dx}\]                 \[=-(0-2Bx)\]           \[F=2Bx\] \[\therefore \]      \[F\propto x\]


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