question_answer

Which alkene on ozonolysis gives\[C{{H}_{3}}C{{H}_{2}}CHO\] and\[C{{H}_{3}}COC{{H}_{3}}\]?

A) \[C{{H}_{3}}C{{H}_{2}}CH=C{{(C{{H}_{3}})}_{2}}\]

B)        \[C{{H}_{3}}C{{H}_{2}}CH=CHC{{H}_{2}}C{{H}_{3}}\]

C)        \[C{{H}_{3}}C{{H}_{2}}CH=CHC{{H}_{3}}\]

D)        \[{{(C{{H}_{3}})}_{2}}CH=CHC{{H}_{3}}\]

Correct Answer: A

Solution :

\[C{{H}_{3}}C{{H}_{2}}CH=CHC{{H}_{2}}C{{H}_{3}}\] \[\xrightarrow[(ii)Zn/{{H}_{2}}O]{(i){{O}_{3}}}2C{{H}_{3}}C{{H}_{2}}CHO\] \[C{{H}_{3}}C{{H}_{2}}CH=CHC{{H}_{3}}\xrightarrow[(ii)Zn/{{H}_{2}}O]{(i){{O}_{3}}}\]                                 \[C{{H}_{3}}C{{H}_{2}}CHO+C{{H}_{3}}CHO\] \[C{{H}_{3}}-\underset{\begin{smallmatrix}  | \\  C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,=CH-C{{H}_{3}}\xrightarrow[(ii)Zn/{{H}_{2}}O]{(i){{O}_{3}}}\]