A) \[C{{H}_{3}}CO{{H}_{2}}\xrightarrow{B{{r}_{2}},\,\,KOH}\]
B) \[C{{H}_{3}}CN\xrightarrow{LiAl{{H}_{4}}}\]
C) \[C{{H}_{3}}NHC\xrightarrow{LiAl{{H}_{4}}}\]
D) \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow{LiAl{{H}_{4}}}\]
Correct Answer: C
Solution :
(a) \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow{B{{r}_{2}},\,\,KOH}\underset{(1{}^\circ \,\,\text{amine)}}{\mathop{C{{H}_{3}}N{{H}_{2}}}}\,\] (b) \[C{{H}_{3}}N\xrightarrow{LiAl{{H}_{4}}}\underset{(1{}^\circ \,\,\text{amine})}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,\] (c) \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow{LiAl{{H}_{2}}}C{{H}_{3}}\underset{(1{}^\circ \,\,\text{amine})}{\mathop{C{{H}_{2}}N{{H}_{2}}}}\,\]
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