A) \[Xe{{O}_{3}}\]
B) \[XePt{{F}_{6}}\]
C) \[Kr{{F}_{2}}\]
D) \[Xe{{F}_{2}}\]
Correct Answer: B
Solution :
Bartlett reacted xenon and platinum hexafluoride in gas phase and an orange yellow solid of \[XePt{{F}_{6}}\] was obtained. \[Xe(g)+Pt{{F}_{6}}(g)\xrightarrow{{}}\underset{Orange\,\,yello}{\mathop{X{{e}^{+}}{{[Pt{{F}_{6}}]}^{-}}(s)}}\,\]
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