RAJASTHAN PMT Rajasthan - PMT Solved Paper-2010

  • question_answer
    For a body moving in a circular path, a condition for no skidding if\[\mu \] is the coefficient of friction, is

    A)  \[\frac{m{{v}^{2}}}{r}\le \mu mg\]                         

    B)  \[\frac{m{{v}^{2}}}{r}\ge \mu mg\]

    C)  \[\frac{v}{r}=\mu g\]    

    D)         \[\frac{m{{v}^{2}}}{r}=\mu mg\]

    Correct Answer: A

    Solution :

    The value of frictional force should be equal or more than required centripetal force,\[~ie,\]\[\mu mg\ge \frac{m{{v}^{2}}}{r}.\]


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