A) \[135{}^\circ C\]
B) \[125{}^\circ C\]
C) \[112{}^\circ C\]
D) \[100{}^\circ C\]
Correct Answer: C
Solution :
Initial volume\[~{{V}_{1}}=47.5\,\,unit\] Temperature of ice cold water \[{{T}_{1}}={{0}^{o}}C=273\,\,K\] Final volume of\[{{V}_{2}}=67\,\,unit\] Applying Charles law, we have\[\frac{{{V}_{1}}}{{{T}_{1}}}=\frac{{{V}_{2}}}{{{T}_{2}}}\] (where temperature \[{{T}_{2}}\] is the boiling point) or \[{{T}_{2}}=\frac{{{V}_{2}}}{{{V}_{1}}}\times {{T}_{1}}=\frac{67\times 273}{47.5}\] \[=385K={{112}^{o}}C\]
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