A) \[{{C}_{V}}=3,\,{{C}_{p}}=5\]
B) \[{{C}_{V}}=4,\,{{C}_{p}}=6\]
C) \[{{C}_{V}}=3,\,{{C}_{p}}=2\]
D) \[{{C}_{V}}=3,\,{{C}_{p}}=4.2\]
Correct Answer: A
Solution :
\[{{C}_{p}}-{{C}_{V}}=R=2\cdot \frac{cal}{gm\text{-}mol\text{-}K}\]which is correct for option (a) and . Further the ratio\[\frac{{{C}_{p}}}{{{C}_{V}}}(=\gamma )\] should equal to some standard value corresponding to that of either, mono, di, or triatomic gases. From this point of view option (a) is correct because\[{{\left( \frac{{{C}_{p}}}{{{C}_{V}}} \right)}_{mono}}=\frac{5}{3}\]
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